Calculating HCO3- in Blood Sample w/ 2.6 X 10^-2 mol/L CO2

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To calculate the HCO3- concentration in arterial blood with 2.6 X 10^-2 mol/L CO2 and a pH of 7.43, the Henderson-Hasselbalch equation is applied. The equation relates the pH to the ratio of bicarbonate (HCO3-) to carbonic acid (H2CO3), leading to the expression 21.4 = (HCO3-)/(H2CO3). The variable x represents the concentration of HCO3-, while the term (2.6 X 10^-2 - x) accounts for the remaining H2CO3 after considering the formation of bicarbonate. This subtraction is necessary to reflect the equilibrium state of the carbonic acid system. The discussion highlights the ambiguity in terminology regarding dissolved CO2 and its forms in solution.
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Homework Statement


A sample of arterial blood was found to contain 2.6 X 10-2 mol/L dissolved CO2. The pH of the sample was 7.43. If it is assumed that in solution the CO2 forms H2CO3, what is the HCO3- concentration in this blood sample? (pKa for H2CO3 is 6.1)


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The Attempt at a Solution


so i first used the henderson hasselbalch equation for the equilibrium H2CO3 <-> HCO3- and then 7.43= 6.1 +log (A-)/(HA) and i got to 21.4= (HCO3-)/(H2CO3). Everything up to here i got, but then in the answer is said to let x= [HCO3-] and therefore 21.4= x / ((2.6X 10^-2)-x)...why do we have to subtract the x from the bottom?
 
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Seems like dissolved CO2 means in this context all forms of carbonate present. But I agree wording is ambiguous.

When referring to buffers we commonly say things like "1M acetate buffer" and we mean sum of concentrations of acetic acid and acetate is 1M.

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