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needhelp83
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An automobile cooling system holds 18 L of water. How much heat does it absorb if its temperature rises from 20oC to 90oC?
V= 18 L=0.018 m3
m=pV=(1.0*103 kg/ m3 )(0.018 m3 )= 18 kg
Q=mcT=(18 kg)(4186 J/kg*Co)( 90o-20o)= 5,274,360 J
The answer in the book says it should be 4.7*10^6, but I don't know how they derived to that answer. Any help
V= 18 L=0.018 m3
m=pV=(1.0*103 kg/ m3 )(0.018 m3 )= 18 kg
Q=mcT=(18 kg)(4186 J/kg*Co)( 90o-20o)= 5,274,360 J
The answer in the book says it should be 4.7*10^6, but I don't know how they derived to that answer. Any help