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j-e_c
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Homework Statement
Assuming a neutron star is made from an incompressible material, what is the hydraulic pressure 50m below the surface?
Mass = 1.98x10^30kg
Radius = 10km
2. The attempt at a solution
g=GM/r^2 = (6.67x10^-11 x 1.98x10^30)/ 10000^2 = 1.32x10^12 m/s^2
P=P[tex]_{0}[/tex] + [tex]\rho[/tex]gh Pa
[tex]\rho[/tex] = m/v = 1.98x10^30 / (4/3 x pi x 10000^3) = 4.73x10^17 kg/m^3
If pressure in space is 0 Pa, then P = 0 + 4.73x10^17 x 1.32x10^12 x 50
= 3.12x10^31 Pa
Is this correct? Thank for your time!
Edit: I think it might be wrong because my equation assumes that space (as a vacuum) and the star are one material (?) :s.
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