Calculating Impulse in a Collision

  • Thread starter itsmarasilly
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In summary, the impulse that acted on the 26 kg object before a collision can be found by calculating the change in velocity (vf - vi) and multiplying it by the mass (26 kg). For part a), the impulse is 52 N*s, and for part b), the impulse is 468 N*s. It is important to correctly identify the initial and final velocities when using the impulse equation.
  • #1
itsmarasilly
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Homework Statement



Before a collision, a 26 kg object is moving at +10 m/s. Find the impulse that acted on the object if, after the collision, it moved at the following velocities.

a) +8.0 m/s
b) -8.0 m/s


Homework Equations



Impulse = change in momentum
= mass * change in velocity
= m * (vf - vi)

The Attempt at a Solution



a) = 26 (+10 m/s - +8.0 m/s), impulse = 52?
b) = 26 (+10 m/s - -8.0 m/s), impulse = 468?
 
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  • #2
Hi itsmarasilly,

itsmarasilly said:

Homework Equations



Impulse = change in momentum
= mass * change in velocity
= m * (vf - vi)

The Attempt at a Solution



a) = 26 (+10 m/s - +8.0 m/s), impulse = 52?
b) = 26 (+10 m/s - -8.0 m/s), impulse = 468?


If you compare these to the last equation in your "Relevant equations" section, it looks like you have the initial and final velocities switched.
 
  • #3
oh okay, got it. thanks! :)
 

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