Calculating Impulse of a Ball Dropped from Rest

In summary, the conversation is about finding the impulse given to a 0.150 kg ball when it is dropped from a height of 1.25m and rebounds to a height of 0.960m. The correct approach is to use the equation I = Δp, with the help of kinematics equations to find the velocities before and after the collision.
  • #1
mickellowery
69
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Homework Statement


A 0.150 kg ball is dropped 1.25m from rest. It rebounds to a height of 0.960m. What is the impulse given to the ball by the floor?


Homework Equations


I=[tex]\Delta[/tex]p and p=mv were the equations I was trying to use. I was pretty sure I should use F=ma since the only other thing that I know is acceleration due to gravity. I don't know anything about time so I ruled out [tex]\int[/tex][tex]\sum[/tex]Fdt.


The Attempt at a Solution

 
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  • #2
mickellowery said:
I=[tex]\Delta[/tex]p and p=mv were the equations I was trying to use.
Good. So how can you figure out the velocity just before and just after it hits the floor?

Hint: When the ball is in the air, it's just a projectile.
 
  • #3
Using I = Δp is the correct approach. Can you find what v just before and just after the collision? If so, then you can find Δv and from this Δp.
 
  • #4
So can I use the kinematics equations? Since I don't know anything about time can I use vf2= vi2+2a (xf-xi) to find the velocity?
 
  • #5
mickellowery said:
So can I use the kinematics equations? Since I don't know anything about time can I use vf2= vi2+2a (xf-xi) to find the velocity?
Sounds good to me.
 
  • #6
thanks kindly to all!
 

FAQ: Calculating Impulse of a Ball Dropped from Rest

What is impulse?

Impulse is a measure of the change in momentum of an object. It is equal to the product of the force applied to the object and the time interval over which it is applied.

How do you calculate impulse?

Impulse is calculated by multiplying the force applied to an object by the time interval over which it is applied. The formula for impulse is J = F * Δt, where J is impulse, F is force, and Δt is the time interval.

What is the relationship between impulse and momentum?

Impulse and momentum are directly related and can be seen as two different ways of expressing the same concept. The impulse experienced by an object is equal to the change in momentum of that object.

What is the impulse of a ball dropped from rest?

The impulse of a ball dropped from rest is equal to the product of its mass and the change in velocity it experiences as it falls. This change in velocity can be calculated using the formula vf = √(vi^2 + 2gh), where vf is the final velocity, vi is the initial velocity (which is zero for a ball dropped from rest), g is the acceleration due to gravity, and h is the height from which the ball is dropped.

How does the height from which a ball is dropped affect its impulse?

The higher the ball is dropped from, the greater its impulse will be. This is because the ball will have a higher velocity and momentum when it hits the ground, resulting in a larger change in momentum and therefore a greater impulse. This relationship can be seen in the formula for impulse, where a larger velocity will result in a larger change in momentum and a greater impulse.

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