- #1
silverbell
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Homework Statement
A ball is thrown into the air a velocity of 49 ft/s. Its height in feet after t seconds is given by y=49t-10t^2.
A. Find the average velocity for the time period beginning when t=3 and lasting
0.01 s:
0.005 s:
B. Estimate the instantaneous velocity when t=3.
Homework Equations
Integrals
The Attempt at a Solution
I'm not exactly sure if I'm approaching this problem at the right angle...
A) 0.01s
1/ [(3.01) -3] ∫ from 3 to 3.01 49t-10t^2 dx
[1/0.01] ∫ from 3 to 3.01 49t-10t^2 dx
[1/0.01] ∫ from 3 to 3.01 (49t^2)/2 - (10t^3)/3 <------ integrated
[1/0.01] [(49(3.01)^2)/2 - (10(3.01)^3)/3] - [1/0.01] [ 49(3)^2)/2 - (10(3)^3)/3
substitution
Same steps for 0.005s
B) I'm not sure how to approach this problem.
Please help me understand the problem. Thank you very much. :)