- #1
andreea_a
- 26
- 0
Hello everyone!
First of all,this is not a homework question :D It's just a problem that I want to solve but I don't know how(it was given at the astronomy olympiad 2011)
Observations were done by the naked eye on June 16, 2008, Universal time was
used. An observer has registered that a star passed zenith at 0 h18m, and at 8h17m its height above the horizon was 87°12'. Find the latitude of the observations.
(you can find it here http://www.issp.ac.ru/iao/2011/ )
I know that if the star passes zenith that means that the zenith distance z = 0 because its height would be 90 degrees.This implies that the latitude is equal to the star's declination.
Then I calculated after the formula: z(zenith distance) = latitude - declination.
z = 90 degrees - 87°12' = 2 degrees and 48 minutes
So,the latitude would be 2 degrees and 48 minutes + declination.But what do I do with that time given ?How do I use it?
I would greatly appreciate your help!
Thanks in advance!
First of all,this is not a homework question :D It's just a problem that I want to solve but I don't know how(it was given at the astronomy olympiad 2011)
Observations were done by the naked eye on June 16, 2008, Universal time was
used. An observer has registered that a star passed zenith at 0 h18m, and at 8h17m its height above the horizon was 87°12'. Find the latitude of the observations.
(you can find it here http://www.issp.ac.ru/iao/2011/ )
I know that if the star passes zenith that means that the zenith distance z = 0 because its height would be 90 degrees.This implies that the latitude is equal to the star's declination.
Then I calculated after the formula: z(zenith distance) = latitude - declination.
z = 90 degrees - 87°12' = 2 degrees and 48 minutes
So,the latitude would be 2 degrees and 48 minutes + declination.But what do I do with that time given ?How do I use it?
I would greatly appreciate your help!
Thanks in advance!