- #1
scarebyte
- 11
- 0
1.find the line integral of
(x^3-y^3)dx +(x^3+y^3)dy over r, where r is the boundary of the
region limited by x^2+y^2=1 and x^2+y^2=9
3.
i found that the
line integral over the curve x^2+y^2=1 is 3*Pi/2
and the double integral of the region limited by x^2+y^2=1 and x^2+y^2=9 is 120*Pi
so the answer would be 120*Pi + 3*Pi/2 ?
(x^3-y^3)dx +(x^3+y^3)dy over r, where r is the boundary of the
region limited by x^2+y^2=1 and x^2+y^2=9
Homework Equations
3.
i found that the
line integral over the curve x^2+y^2=1 is 3*Pi/2
and the double integral of the region limited by x^2+y^2=1 and x^2+y^2=9 is 120*Pi
so the answer would be 120*Pi + 3*Pi/2 ?