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Homework Statement
a rod with mass 'M' and length 'L' is pivoted about a frictionless axle through it's end .a bullet with mass 'm' and speed 'v' is shot and sticks to the rod a distance 'a' from the axle.
I need to find the LINEAR momentum of the system just after the hit.
Homework Equations
moment of inertia of a rod about it's center of mass: I=(1/12)*M*L^2
L = I*(omega)
p = (m+M)*V
The Attempt at a Solution
the intial angular momentum is: mva (about the pivot)
angular momentum after the hit is just: I*omega
where I = (1\3)*M*L^2 + m*(a^2)
equating those two gives omega,by the relation V=omega*L
we can get the speed V,so P = (m+M)*V
and this is not the answer
thanks for the help
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