Calculating Magnetic Flux in a Bent Square Loop with a Uniform Magnetic Field

[BuBbLeS01]

Magnetic flux...PLEASE HELP!

Homework Statement

A 13.5 cm × 13.5 cm square bent at a angle 90°. A uniform 0.463 T magnetic field points downward at θ=33° angle. What is the magnetic flux through the loop? (a=6.75 cm, b=13.5 cm, c=6.75 cm.)

Homework Equations

The Attempt at a Solution

MF = AB cos theta
Would it just be (.135 * .135) * 0.463 cos 33
I am not sure which area and angle to use?

 

[BuBbLeS01]

nevermind got it

 

[Moetasim]

To calculate the magnetic flux through the loop, you can use the formula MF = AB cos θ, where A is the area of the loop and θ is the angle between the magnetic field and the normal to the loop. In this case, A = 13.5 cm * 6.75 cm = 91.125 cm^2 and θ = 33°. Plugging these values into the formula, we get MF = (91.125 cm^2) * (0.463 T) * cos 33° = 38.98 mT*cm^2. Therefore, the magnetic flux through the loop is 38.98 mT*cm^2.