- #1
brunie
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A proton travels with a speed of 3.00 x 10^6 m/s at an angle of 44.0° with the direction of a magnetic field of 0.730 T in the +y direction.
(a) What are the magnitude of the magnetic force on the proton?
(b) What is its acceleration?
Ok for magnitude of force,
I used F = qvB sinø
= (1.6E-19)(3E6)(.73)sin44
= 2.437 E-13
But I was unable to find an equation for aceleration in a magnetic field in my notes, can anyone help me out?
Thanks
(a) What are the magnitude of the magnetic force on the proton?
(b) What is its acceleration?
Ok for magnitude of force,
I used F = qvB sinø
= (1.6E-19)(3E6)(.73)sin44
= 2.437 E-13
But I was unable to find an equation for aceleration in a magnetic field in my notes, can anyone help me out?
Thanks