Calculating Magnetic Force and Acceleration of a Proton

In summary, the proton is moving at a speed of 3.00 x 10^6 m/s at an angle of 44.0° with a magnetic field of 0.730 T in the +y direction. To find the magnitude of the magnetic force on the proton, the formula F = qvB sinø is used, resulting in a value of 2.437 E-13. The acceleration of the proton can be found using the formula Fnet = ma, where the net force incorporates the magnetic force. The right hand rule is important in determining the direction of the force, which affects the direction of the velocity vector and therefore the acceleration. The equation for acceleration involves fnet = ma, where fnet
  • #1
brunie
62
0
A proton travels with a speed of 3.00 x 10^6 m/s at an angle of 44.0° with the direction of a magnetic field of 0.730 T in the +y direction.

(a) What are the magnitude of the magnetic force on the proton?
(b) What is its acceleration?

Ok for magnitude of force,

I used F = qvB sinø
= (1.6E-19)(3E6)(.73)sin44
= 2.437 E-13

But I was unable to find an equation for aceleration in a magnetic field in my notes, can anyone help me out?

Thanks
 
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  • #2
What does the path of the motion look like?
 
  • #3
lol i have no idea,
but could this be solved just by using Fnet = ma
where Fnet incorporates the magentic force and gravitational force?
 
  • #4
I doubt you need to include gravitational effects here.
The path of the motion is a hint as to how to find the solution. Any guesses?
 
  • #5
well i kno initially its moving at the angle of 44˚, but the magnetic field should affect it to move in the positive y direction i think
 
  • #6
Oh, you need to revisit the right hand rule to determine the direction of the force. This is an important effect for these types of problems.
 
  • #7
but wouldn't using the RHR in this case introduce the 3rd dimension, because it would be coming out ?
 
  • #8
?
 
  • #9
yes, from the cross product.
 
  • #10
so if we know it is coming out, how does it help solve for acceleration?
 
  • #11
So at that point the force is out, does it remain in that direction?
 
  • #12
i assume so
 
  • #13
If the object has a net force acting on it, it will accelerate in that direction. So the velocity changes; remember that the direction of the force is dependent on the direction of the velocity vector, which changes.
 
  • #14
so is there a way/formula to solve for acceleration by knowing this?
 
  • #15
Sorry, if you are looking for me to give you a formula to plug numbers into, I can't help you.
If you understand the motion in your mind's eye, you will recognize the solution (hopefully).
 
  • #16
fyi, i was right,
the equation has to do with fnet = ma
where fnet incorporates magnetic force

so next time if u don't kno wut ur talking about please don't answer a question for sum1... instead of saying ok wut u said might make sense u overcomplicate everything
 
  • #17
My apologies, I was for some reason thinking we were looking for the radius of motion.
My bad :smile:
In my opinion, I do not think that the questions I prompted were useless. I still think you should try to understand the motion of the charged object through the B field. :rolleyes:
 

FAQ: Calculating Magnetic Force and Acceleration of a Proton

What is the formula for calculating the magnetic force on a proton?

The formula for calculating the magnetic force on a proton is F = qvB, where F is the force in Newtons, q is the charge of the proton in Coulombs, v is the velocity of the proton in meters per second, and B is the strength of the magnetic field in Tesla.

How do you calculate the acceleration of a proton in a magnetic field?

The acceleration of a proton in a magnetic field can be calculated using the formula a = qvB/m, where a is the acceleration in meters per second squared, q is the charge of the proton in Coulombs, v is the velocity of the proton in meters per second, B is the strength of the magnetic field in Tesla, and m is the mass of the proton in kilograms.

What is the direction of the magnetic force on a proton?

The direction of the magnetic force on a proton is perpendicular to both the velocity of the proton and the magnetic field. The direction can be determined using the right hand rule, where the thumb represents the direction of the magnetic force, the index finger represents the direction of the magnetic field, and the middle finger represents the direction of the proton's velocity.

How does the magnetic field strength affect the acceleration of a proton?

The magnetic field strength has a direct relationship with the acceleration of a proton. As the strength of the magnetic field increases, the acceleration of the proton also increases. This can be seen in the formula a = qvB/m, where B is directly proportional to the acceleration.

Can the magnetic force and acceleration of a proton be negative?

Yes, the magnetic force and acceleration of a proton can be negative if the proton is moving in the opposite direction of the magnetic field. This can be seen in the formula a = qvB/m, where the negative sign indicates the opposite direction of the magnetic force and acceleration.

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