Calculating Magnetic Moment of Hydrogen Atom

In summary, the magnetic moment of a hydrogen atom can be calculated by using the equation I = qv/(2*pi*r), where q represents the charge of an electron, v is the velocity of the electron, and r is the radius of the atom. After correcting a typo and normalizing by the distance, the result obtained was 3.77*10^-22.
  • #1
iontail
24
0

Homework Statement



find the magnetic moment of a hydrogen atom given that the election moves at 0.10c around the nucleus and the radius is 0.5*10^-5 m

Homework Equations



n/a

The Attempt at a Solution



this is what i did.

I = nev
=ev (I = current e= charge of electron, v = velocity)

m = IA (A = area)

my result is 12 A m^2.

The result looks too big...am I doing something wrong. can you please verify that my answer is right.
 
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  • #2
iontail said:
I = nev
=ev (I = current e= charge of electron, v = velocity)
What's n?

Hint: Find the current by figuring out long it takes for the electron to orbit the nucleus.
 
  • #3
Your approach is correct, you may want to check your units.

e = 1.6*10^-19 coulomb
v = 3*10^7 m/s
r = 0.5*10^-5 m

I = q v
m = I pi r^2

I get:

I = 4.8*10^-12
m = 3.77*10^-22
 
  • #4
jpreed said:
I = q v
You might want to rethink that equation.
 
  • #5
Doc Al said:
You might want to rethink that equation.


hi sorry about that i made a typo.
n=number of free electron

and I = nev/(r*pi*r) (r= radius of atom)

the answer i got before is still correct. I just made a typo while putting the detials in the computer.

I am just suprised that the magnetic moment for an atom is so high. CAn you please verify the answer. or tell me if i have made any other mistake.
 
  • #6
iontail said:
hi sorry about that i made a typo.
n=number of free electron
OK, so n = 1.

and I = nev/(r*pi*r) (r= radius of atom)
That doesn't look right. (Check the units.)
 
  • #7
Doc Al said:
OK, so n = 1.


That doesn't look right. (Check the units.)

I = ev/2*pi*r

it should be right now.
 
  • #8
iontail said:
I = ev/2*pi*r

it should be right now.
Now you've got it.
 
  • #9
Doc Al said:
You might want to rethink that equation.

Oops, I forgot to normalize by the distance. You are right.

It should be

I = q v / (2 pi r)
 
  • #10
jpreed said:
Oops, I forgot to normalize by the distance. You are right.

It should be


I = q v / (2 pi r)


thabk you all for you help...
 

FAQ: Calculating Magnetic Moment of Hydrogen Atom

What is the formula for calculating the magnetic moment of a hydrogen atom?

The formula for calculating the magnetic moment of a hydrogen atom is μ = -e/2m * L, where μ is the magnetic moment, e is the charge of the electron, m is the mass of the electron, and L is the orbital angular momentum of the electron.

How do you calculate the orbital angular momentum of an electron in a hydrogen atom?

The orbital angular momentum of an electron in a hydrogen atom can be calculated using the formula L = √(l(l+1)) * h/2π, where l is the orbital quantum number and h is Planck's constant.

What is the value of the magnetic moment of a hydrogen atom?

The value of the magnetic moment of a hydrogen atom is approximately +9.274 x 10^-24 J/T. However, this value may vary slightly depending on the exact energy level and spin state of the electron.

Why is the magnetic moment of a hydrogen atom important in physics?

The magnetic moment of a hydrogen atom is important in physics because it helps to explain the behavior of atoms in a magnetic field. It also plays a crucial role in the study of quantum mechanics and the interactions between particles.

What is the significance of a non-zero magnetic moment for a hydrogen atom?

A non-zero magnetic moment for a hydrogen atom indicates that the electron is not moving in a perfect circular orbit, but rather has some angular momentum and is affected by external magnetic fields. This has important implications in understanding the structure and properties of atoms and molecules.

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