Calculating Marble's Initial Height Using Projectile Motion Equations

[IAmSparticus]

Homework Statement

A marble is thrown horizontally with a speed of 10 m/s from the top of a building. When it strikes the ground, the marble has a velocity that makes an angle 68° with the horizontal. From what height above the ground was the marble thrown?

Homework Equations

delta y = (V02 sin2 theta)/(2g)

The Attempt at a Solution

4.39 m and 421.24. Neither correct.

 

[tiny-tim]

Hi IAmSparticus!

Show us your full calculations, and then we can see what went wrong, and we'll know how to help!

 

[tomcue]

I would like to point out that the equation used in the attempt at a solution is incorrect. The correct equation to use in this scenario is delta y = (V0^2 sin^2 theta)/(2g), where V0 is the initial velocity, theta is the angle of the velocity, and g is the acceleration due to gravity.

Additionally, it is important to note that the given information is not enough to accurately calculate the initial height of the marble. The equation only provides the vertical displacement, but in order to determine the initial height, we would also need the horizontal displacement. Without this information, the initial height cannot be accurately calculated using projectile motion equations.

Furthermore, it is important to consider the limitations of using projectile motion equations in real-world scenarios. Factors such as air resistance, wind, and the shape of the object can all affect the trajectory of the marble and may lead to inaccurate results when using simplified equations. It is important to take these factors into account when conducting experiments or making calculations involving projectile motion.