- #1
xdeanna
- 24
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Each of the four wheels of a car pushes on the road with a force of 4.0 x 10³ N [down]. The driving force on the car is 8.0 x 10³ N [W]. The frictional resistance on the car is 6.0 x 10³ N [E]. Calculate the following:
(a) mass of the car
(b) net force on the car
(c) car's acceleration
For Fnet, would u also add 4(4.0 x 10³ N [up]) to the rest of vectors to cancel out the force all the tires have on the road? Or:
8.0 x 10³ N [W] + 6.0 x 10³ N [E]= 2.0 x 10³ N [W]
2.0 x 10³ N [W] + 4(4.0 x 10³ N [down])= Fnet
?!
I just did all that on my phone.. I'm desperate for some help :(
(a) mass of the car
(b) net force on the car
(c) car's acceleration
For Fnet, would u also add 4(4.0 x 10³ N [up]) to the rest of vectors to cancel out the force all the tires have on the road? Or:
8.0 x 10³ N [W] + 6.0 x 10³ N [E]= 2.0 x 10³ N [W]
2.0 x 10³ N [W] + 4(4.0 x 10³ N [down])= Fnet
?!
I just did all that on my phone.. I'm desperate for some help :(