- #1
UrbanXrisis
- 1,196
- 1
A lamina occupies the part of the disk [tex]x^2+y^2=<25[/tex] in the first quadrant and the density at each point is given by the function [tex] \ro (x,y)=3(x^2+y^2)[/tex]
i am to find the mass, so this is what i did:
[tex]\int _0 ^{ \frac{\pi}{ 2}} \int _0 ^{5}(3 r) r dr d \theta[/tex]
i evauated this and got pi/2 15^3... but this is wrong, not sure why
i am to find the mass, so this is what i did:
[tex]\int _0 ^{ \frac{\pi}{ 2}} \int _0 ^{5}(3 r) r dr d \theta[/tex]
i evauated this and got pi/2 15^3... but this is wrong, not sure why