- #1
zaraox
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A 1.2 kilogram block is dropped from 0.48m above a spring in equilibrium. The force constant for the spring is 124 N/m. Calculate the maximum compression in the spring.
m = 1.2 kg
h = 0.48 + x
k = 124 N/m
x = ?
Ep = mgh
Ep = (1.2)(9.8)(0.48 + x)
Ep = 11.76(0.48 + x)
Ep = 5.6448 +11.76x
Sadly, that's as far as I get... if anyone could guide me through the next steps, it'd be greatly appreciated!
m = 1.2 kg
h = 0.48 + x
k = 124 N/m
x = ?
Ep = mgh
Ep = (1.2)(9.8)(0.48 + x)
Ep = 11.76(0.48 + x)
Ep = 5.6448 +11.76x
Sadly, that's as far as I get... if anyone could guide me through the next steps, it'd be greatly appreciated!
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