Calculating Maximum Torque for a Shaft with Multiple Components

[stompin]

I have a question regarding the maximum rotational force applied to a shaft, I am trying to work out the maximum force a one way bearing will be subjected to.

What I've got is a honda gx240 motor, creating 15.3Nm of torque, which goes through a torque converter (cvt) which has a maximum torque multiplication of 2.7:1 then a chain is used to link the shaft with a 12/60 tooth sprockets creating a 5:1 ratio. In theory this would equate to a maximum torque of 206Nm (15.3 *2.71 *5) of torque.

What I am not sure about is how the diameter of the 60 tooth sprocket (say 6" in diameter) plays its part in the torque on the shaft?

Can some one advise me if I am on the right track?

Thanks Brad

 

[Navin A S]

Yes, you are on the right track. The diameter of the sprocket will not affect the amount of torque being transmitted to the shaft, but it will affect the angular velocity of the shaft. As a result, the maximum rotational force applied to the shaft is equal to the torque multiplied by the radius of the sprocket (6 inches in this case). So, the maximum force applied to the shaft is 206Nm * 6in = 1236 lb-ft.