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higherme
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A 5.62-g sample containing only Mn2(SO4)3(s) and Al2(SO4)3(s) is dissolved in aqueous solution. The metal ions are precipitated as hydroxides, which are pyrolyzed in air to produce 2.06 g of a mixture of Mn2O3(s) and Al2O3(s).
What was the percent Mn in the original sample?
what i did so far:
found molar mass of Mn2O3 and Al2O3
157.873g/mol and 101.961 g/mol respectively
total 259.834g/mol
Mn2O3 takes up 60.76% of the total molar mass and Al2O3 takes up 39.24%.
so does that mean 60.76% of the 2.06 g mixture would be Mn2O3 and 39.24% would be from Al2O3?
Then i don't know what to do next
help?
What was the percent Mn in the original sample?
what i did so far:
found molar mass of Mn2O3 and Al2O3
157.873g/mol and 101.961 g/mol respectively
total 259.834g/mol
Mn2O3 takes up 60.76% of the total molar mass and Al2O3 takes up 39.24%.
so does that mean 60.76% of the 2.06 g mixture would be Mn2O3 and 39.24% would be from Al2O3?
Then i don't know what to do next
help?