- #1
shaklove
- 1
- 0
can you guys help me pleasee
The relationship between resistance with temperature is expressed by the equation of R= R0[1+ α(T-T0)], where Ro is the resistance at the reference temp. T0 and α for the resistor material has been determined to be 0.0048 ± 0.1% oC. In the range 0 to 100* C, in which we are calibrating this resistor, temperature measurements have shown a standard deviation of 0.1* C. The systematic uncertainty of the temperature- measurement device is known to be 0.1* C.
At 0* C, the resistance is 100.00 Ω. compute the percent uncertainty of R, at a temperature of 25* C with a 95% confidence level
Wx = (Bx^2 + Px^2)^ 1/5
I know that the confidence level is = 1 - a (alpha)
0.95 = 1 - a >>>>>>> a = 1 - 0.95 = 0.05
a/2 = 0.025
i know that i can use this formula Px = tSx
Should i assume that "t" is 2 , then i say Px = 2 * (0.1) = 0.2
am not sure of am right !
Homework Statement
The relationship between resistance with temperature is expressed by the equation of R= R0[1+ α(T-T0)], where Ro is the resistance at the reference temp. T0 and α for the resistor material has been determined to be 0.0048 ± 0.1% oC. In the range 0 to 100* C, in which we are calibrating this resistor, temperature measurements have shown a standard deviation of 0.1* C. The systematic uncertainty of the temperature- measurement device is known to be 0.1* C.
At 0* C, the resistance is 100.00 Ω. compute the percent uncertainty of R, at a temperature of 25* C with a 95% confidence level
Homework Equations
Wx = (Bx^2 + Px^2)^ 1/5
The Attempt at a Solution
I know that the confidence level is = 1 - a (alpha)
0.95 = 1 - a >>>>>>> a = 1 - 0.95 = 0.05
a/2 = 0.025
i know that i can use this formula Px = tSx
Should i assume that "t" is 2 , then i say Px = 2 * (0.1) = 0.2
am not sure of am right !