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future_vet
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We have 45.0g of Na3PO4 per liter. We know it is very basic but need the pH.
I don't have the answers to all exercises, so if you could check my work, that'd be great.
So, we have g, but moles would be more useful.
So 45g x (1 mol/163.937) = 2.7 x 10^-1 mol.
We know that strong bases completely dissociate in water.
Therefore, [Na3PO4]=[OH-].
So, since pOH = - log of all that = 0.569
Therefore: pH = 14 - 0.569 = 13.431 which is indeed pretty basic.
Any mistake somewhere?
Thank you,
Joanna.
I don't have the answers to all exercises, so if you could check my work, that'd be great.
So, we have g, but moles would be more useful.
So 45g x (1 mol/163.937) = 2.7 x 10^-1 mol.
We know that strong bases completely dissociate in water.
Therefore, [Na3PO4]=[OH-].
So, since pOH = - log of all that = 0.569
Therefore: pH = 14 - 0.569 = 13.431 which is indeed pretty basic.
Any mistake somewhere?
Thank you,
Joanna.
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