- #1
cjm181
- 69
- 1
Hi
This i suspect is a very silly question. I have a battery charger for rc helis. The charger is supplied with 24Vdc via a pair of computer power supplies. The PSU's are supplied with 240Vac from the wall. I am trying to size up a generator so i can charge at the field.
The charger has two channels, ie it can charge two batteries at once.
The batteries are 6s (22.1V), 3300mA. So for my charger each of them at 4A, the charger will be drawing 24Vdc (thats what the PSU's deliver), and 8A.
So the Power required at the charger input is:
P (W) = I (A) x V
P = 24 x 8 = 192W
So, the supply to the PSU's from the mains is 240Vac, can i use the above numbers to calculate what the amps are coming from the wall? so:
192 = 240 x I
I = 192 / 240 = 0.8A?
So the power at the charger is the same that's coming from the wall?
Back to the generator, if the generator can supply 230Vac @ 1600W, it can supply:
I = 1600 / 230 = 6.9A
But assuming the power is the same anywhere in the setup, if the charger is receiving 1600W at its input, the max amperage the charger can charge at is:
I = 1600 / 24 = 66A?
Are my sumations somewhere near?
Thanks
Craig
This i suspect is a very silly question. I have a battery charger for rc helis. The charger is supplied with 24Vdc via a pair of computer power supplies. The PSU's are supplied with 240Vac from the wall. I am trying to size up a generator so i can charge at the field.
The charger has two channels, ie it can charge two batteries at once.
The batteries are 6s (22.1V), 3300mA. So for my charger each of them at 4A, the charger will be drawing 24Vdc (thats what the PSU's deliver), and 8A.
So the Power required at the charger input is:
P (W) = I (A) x V
P = 24 x 8 = 192W
So, the supply to the PSU's from the mains is 240Vac, can i use the above numbers to calculate what the amps are coming from the wall? so:
192 = 240 x I
I = 192 / 240 = 0.8A?
So the power at the charger is the same that's coming from the wall?
Back to the generator, if the generator can supply 230Vac @ 1600W, it can supply:
I = 1600 / 230 = 6.9A
But assuming the power is the same anywhere in the setup, if the charger is receiving 1600W at its input, the max amperage the charger can charge at is:
I = 1600 / 24 = 66A?
Are my sumations somewhere near?
Thanks
Craig