- #1
nns91
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Homework Statement
A 1200kg elevator driven by an electric motor can safely carry a maximum load of 800kg. What is the power provided by the motor when the elevator ascends with a full load at a speed of 2.3 m/s
Homework Equations
P=F*v
The Attempt at a Solution
So I use directly P=F*v=(melevator+mpeople)*g*v
However I got the wrong answer. Does it involve any other formula here ?