Calculating pressure from a known equation of energy

In summary: I also made a little progress on this by using dimensional analysis . This helped me to identify the function f(V) which is proportional to R/V, and it also gave me an equation for the pressure, which is P=\frac{gT^a}{a-1}+Tf(V).
  • #1
ForgetfulPhysicist
31
2
Homework Statement
Heat Engine with working substance characterized by energy E = g T^a V, with a>1 and g>0 being known coefficients. The values of P1, V1 are also known. Find P2 /P1 in terms of the known quantities.
Relevant Equations
dE = TdS - PdV
Screen Shot 2023-03-18 at 7.19.06 PM.png


My attempted solution is as follows:

Obviously the heat transfer happens during transitions 1->2 and 3->1.

It's also clear that
P1 = P3
V1 = V2

E2 - E1 = Integral[T dQ , from state 1 to state 2]

E3 - E2 = - Integral[P dV , from state 2 to state 3]

E1 - E3 = Integral[T dQ , from state 3 to state 1] + 7 P1 V1

But I can't find a way to perform any of these integrals or make any progress on this problem.

An attempt to calculate pressure is stuck at: p = - (dE/dV)_S = g a T^(a-1) (dT/dV)_S V + g T^a
 
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  • #2
ForgetfulPhysicist said:
E2 - E1 = Integral[T dQ , from state 1 to state 2]

E1 - E3 = Integral[T dQ , from state 3 to state 1] + 7 P1 V1
Check the units in these equations.
 
  • #3
Philip Koeck said:
Check the units in these equations.
Yes that was a typo. They should be written:
E2 - E1 = Integral[dQ , from state 1 to state 2]
E1 - E3 = Integral[dQ , from state 3 to state 1] + 7 P1 V1

One idea: I can calculate Cv = (dE/dT)_V = a g T^(a-1) V , and I also know Cv = T (dS/dT)_V which helps me know a little bit about the change of entropy from state 1 to 2.... but I'm still stuck.
 
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  • #4
ForgetfulPhysicist said:
Yes that was a typo. They should be written:
E2 - E1 = Integral[dQ , from state 1 to state 2]
E1 - E3 = Integral[dQ , from state 3 to state 1] + 7 P1 V1

One idea: I can calculate Cv = (dE/dT)_V = a g T^(a-1) V , and I also know Cv = T (dS/dT)_V which helps me know a little bit about the change of entropy from state 1 to 2.... but I'm still stuck.
I also made a little progress on this by using $$\left(\frac{\partial E}{\partial V}\right)_T=-\left[P-T\left(\frac{\partial P}{\partial T}\right)_V\right]=gT^a$$which leads to $$P=\frac{gT^a}{a-1}+Tf(V)$$
 
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  • #5
I derived the equation for entropy variation also, but I've as yet not been able to figure out a way that it can be used to provide an answer to this problem: $$dS=\frac{ga}{(a-1)}d(T^{a-1}V)+f(V)dV$$
 
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  • #6
From dimensional considerations, it makes sense to me that the function f(V) should be proportional to R/V, where R is the gas constant. If f(V) were equal to R/v, we would have $$\frac{PV}{RT}=z=1+\frac{1}{a-1}\frac{E}{RT}$$I'm unable to prove this yet, but I may proceed as if it is the case and see where it takes me.
 

FAQ: Calculating pressure from a known equation of energy

What is the relationship between energy and pressure?

The relationship between energy and pressure often depends on the specific context or system being analyzed. In thermodynamics, pressure can be related to energy through the equation of state, such as the ideal gas law, where PV = nRT. Here, pressure (P) is directly related to the energy (temperature, T) of the gas. In more complex systems, the relationship may involve additional variables and constants.

How can I derive pressure from the internal energy of an ideal gas?

For an ideal gas, the internal energy (U) is related to temperature (T) and can be expressed as U = (3/2)nRT for a monatomic ideal gas. Using the ideal gas law PV = nRT, you can solve for pressure (P) as P = (2/3)(U/V), where V is the volume of the gas. This shows that pressure is proportional to the internal energy per unit volume.

What is the equation to calculate pressure from energy in a fluid system?

In a fluid system, the pressure (P) can be related to energy density (u) through the equation P = (γ - 1)u, where γ is the adiabatic index or specific heat ratio (Cp/Cv). This equation is derived from the first law of thermodynamics and is applicable to adiabatic processes.

Can pressure be calculated from kinetic energy?

Yes, pressure can be calculated from the kinetic energy of particles in a system. For an ideal gas, the kinetic theory of gases provides the relation P = (2/3)(E_kin/V), where E_kin is the total kinetic energy of the gas molecules and V is the volume. This equation shows that pressure is proportional to the average kinetic energy per unit volume.

How does the equation of state help in calculating pressure from energy?

The equation of state provides a relationship between state variables such as pressure, volume, and temperature. For example, the ideal gas law (PV = nRT) allows us to calculate pressure if the energy (temperature) and volume are known. More complex equations of state, like the van der Waals equation, can also be used to relate pressure to energy in non-ideal gases by accounting for intermolecular forces and finite molecular size.

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