Calculating pressure of air pocket in a pressurized water column

In summary, the speaker is seeking guidance on calculating the pressure of an air pocket in a pressurized water column. They mention a 2" vertical pipe with 2" of air and 40 psi water applied. The water pressure is measured at the bottom of the 24" column, where the air is located. The speaker also asks about the pressure drop along the column.
  • #1
cvsanders
2
0
TL;DR Summary
Calculating pressure of air pocket in pressurized water column.
Looking for some guidance in calculating pressure of air pocket in pressurized water column. Example: 2" vertical pipe, capped, with 2" of air and 40 psi water applied.
 
Engineering news on Phys.org
  • #2
Welcome to PF. :smile:

Presumably the air bubble is at the top of the column, right? Where are you measuring the 40psi water pressure? At the top or bottom of the water column? How tall is the pipe?
 
  • #3
Water supply line pressure is 40 psi, air is at top of 24" column, where it is being read.
 
  • #4
So the 24" tall pipe has 40psi water at the bottom. How much does the pressure drop going up that water column...? :smile:
 

Related to Calculating pressure of air pocket in a pressurized water column

What is the basic principle behind calculating the pressure of an air pocket in a pressurized water column?

The basic principle involves applying the hydrostatic pressure formula, which states that the pressure at a given depth in a fluid is equal to the atmospheric pressure plus the product of the fluid's density, gravitational acceleration, and the depth of the fluid column above the point of measurement.

How do you account for the atmospheric pressure when calculating the pressure of the air pocket?

To account for atmospheric pressure, you add it to the pressure exerted by the water column. The total pressure on the air pocket is the sum of the atmospheric pressure and the pressure due to the water column, calculated using the hydrostatic pressure formula.

What role does the density of water play in calculating the pressure of the air pocket?

The density of water is a crucial factor because it directly affects the hydrostatic pressure. The pressure exerted by the water column is proportional to the water's density. Higher density results in greater pressure at a given depth.

How does the depth of the water column influence the pressure of the air pocket?

The depth of the water column is directly proportional to the pressure exerted by the water. As the depth increases, the pressure increases linearly. This is because the weight of the water column above the air pocket increases with depth, thus increasing the pressure.

What is the formula to calculate the pressure of an air pocket in a pressurized water column?

The formula to calculate the pressure of an air pocket in a pressurized water column is: \( P = P_{\text{atm}} + \rho \cdot g \cdot h \), where \( P \) is the total pressure, \( P_{\text{atm}} \) is the atmospheric pressure, \( \rho \) is the density of water, \( g \) is the acceleration due to gravity, and \( h \) is the depth of the water column.

Similar threads

Replies
16
Views
3K
  • Mechanical Engineering
Replies
2
Views
500
  • Mechanical Engineering
Replies
12
Views
2K
Replies
8
Views
1K
Replies
3
Views
664
  • Mechanical Engineering
Replies
20
Views
8K
Replies
10
Views
5K
Replies
1
Views
2K
  • Mechanical Engineering
Replies
28
Views
2K
Back
Top