- #1
Somefantastik
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Given 4 flips of a fair coin, what is the probability of {H,H,H,H}?
I thought since flips of a fair coin are independent, then P(H&H&H&H) = P(H)P(H)P(H)P(H) = 1/(2^4) = 1/16. Am I close?
I thought since flips of a fair coin are independent, then P(H&H&H&H) = P(H)P(H)P(H)P(H) = 1/(2^4) = 1/16. Am I close?