- #1
chimychang
- 5
- 0
I need some help on the following question: Let N() be a poisson process with parameter [tex] \lambda [/tex].
I need to find that probability that
[tex] N((1,2]) = 3 [/tex] given [tex] N((1,3]) > 3 [/tex]
I know that this is equal to the probability that
[tex] P(A \cap B) / P(B) [/tex] where A = N((1,2]) and B = N((1,3]) > 3, but I'm not sure where to go from there.
I need to find that probability that
[tex] N((1,2]) = 3 [/tex] given [tex] N((1,3]) > 3 [/tex]
I know that this is equal to the probability that
[tex] P(A \cap B) / P(B) [/tex] where A = N((1,2]) and B = N((1,3]) > 3, but I'm not sure where to go from there.