- #1
dagg3r
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a radioactive with a half-life of 5 days, has an initial activity of 4000 counts/min
determine the activity after 10 days
well because 1 half life is 5 days, so 10 days must be 2
so 4000/(2^2)
=1000 counts/min is that right?
2. If the initial quantitiy of radioactive material is 200gms determine the amount left after 15 days have elapsed
no of half lives = 3
200/(2^3)
=25 gms is that right?
3. convert 4000 counts per min into bq's
how do i do that?
determine the activity after 10 days
well because 1 half life is 5 days, so 10 days must be 2
so 4000/(2^2)
=1000 counts/min is that right?
2. If the initial quantitiy of radioactive material is 200gms determine the amount left after 15 days have elapsed
no of half lives = 3
200/(2^3)
=25 gms is that right?
3. convert 4000 counts per min into bq's
how do i do that?