MHB Calculating Ratio of $\overline{BP}$ to $\overline {PN}$ in Hexagon $ABCDEF$

  • Thread starter Thread starter Albert1
  • Start date Start date
  • Tags Tags
    Hexagon Ratio
AI Thread Summary
In a regular hexagon $ABCDEF$, points $M$ and $N$ are identified as the midpoints of sides $\overline{CD}$ and $\overline{DE}$. The intersection point $P$ is formed by lines $\overline{AM}$ and $\overline{BN}$. The goal is to calculate the ratio $\dfrac {\overline{BP}}{\overline {PN}}$. The geometric properties of the hexagon and the midpoints play a crucial role in determining this ratio. The solution involves applying principles of symmetry and proportionality inherent in regular hexagons.
Albert1
Messages
1,221
Reaction score
0
Regular hexagon $ABCDEF$,points $M$ and $N$ are midpoints of $\overline{CD}$
and $\overline {DE}$ respectively, point $P$ is the intersection of $\overline {AM}$ and $\overline{BN}$
Find $\dfrac {\overline{BP}}{\overline {PN}}$
 
Mathematics news on Phys.org
Albert said:
Regular hexagon $ABCDEF$,points $M$ and $N$ are midpoints of $\overline{CD}$
and $\overline {DE}$ respectively, point $P$ is the intersection of $\overline {AM}$ and $\overline{BN}$
Find $\dfrac {\overline{BP}}{\overline {PN}}$

 

Attachments

  • BP over  PN.jpg
    BP over PN.jpg
    25.4 KB · Views: 113
Last edited by a moderator:
Seemingly by some mathematical coincidence, a hexagon of sides 2,2,7,7, 11, and 11 can be inscribed in a circle of radius 7. The other day I saw a math problem on line, which they said came from a Polish Olympiad, where you compute the length x of the 3rd side which is the same as the radius, so that the sides of length 2,x, and 11 are inscribed on the arc of a semi-circle. The law of cosines applied twice gives the answer for x of exactly 7, but the arithmetic is so complex that the...
Is it possible to arrange six pencils such that each one touches the other five? If so, how? This is an adaption of a Martin Gardner puzzle only I changed it from cigarettes to pencils and left out the clues because PF folks don’t need clues. From the book “My Best Mathematical and Logic Puzzles”. Dover, 1994.

Similar threads

Replies
1
Views
1K
Replies
3
Views
2K
2
Replies
93
Views
11K
3
Replies
104
Views
17K
Replies
4
Views
3K
Replies
3
Views
2K
Back
Top