- #1
Punch
- 44
- 0
Homework Statement
A relay switches on when the current through the coil reaches 0.0048A.
In a circuit, a battery of 12V is connected in series with this relay it switches on when another resistor of 800 Ohm is connected to it.
Calculate the resistance of the relay.
Homework Equations
The Attempt at a Solution
V= IR
12V = 0.0048A * (800 ohm + coil resistance)
12V / 0.0048A = 800 ohm + coil resistance
coil resistance = 2500 ohm - 800 ohm
=1700 ohm
However, I am not sure if I am on the right track...
Last edited: