- #1
AlexTheFirst
- 4
- 0
Hi everyone!
I'm trying to figure out how to go about this in calculating resistivity of a titanium grade 1 mesh. From what I know the ρ for titanium is 4.3x10^-8 ohm x m. The mesh will be a 1x12inch sheet wrapped cylindrically end to end. Here are the stock values including a change in area. Les also say the temperature of the material is 20°C and grade 1 is equal to 99.9% pure so let's just round that to 100% and ignore impurities.
Area: 12x12inches
Wire diameter: 0.0020inches = 0.0508mm
Width Opening: 0.0080 inches = 0.2032mm
Wire Mesh (wires/in): 100 x 100
% open Area: 64%
ρ for titanium is 4.3x10^-8 ohm x m
I was thinking of using
R=(ρ)(Length)/(cross section area of wire)
im not an electrical engineer, so any guidance what's so ever would be a great help. Thank you everyone.
I'm trying to figure out how to go about this in calculating resistivity of a titanium grade 1 mesh. From what I know the ρ for titanium is 4.3x10^-8 ohm x m. The mesh will be a 1x12inch sheet wrapped cylindrically end to end. Here are the stock values including a change in area. Les also say the temperature of the material is 20°C and grade 1 is equal to 99.9% pure so let's just round that to 100% and ignore impurities.
Area: 12x12inches
Wire diameter: 0.0020inches = 0.0508mm
Width Opening: 0.0080 inches = 0.2032mm
Wire Mesh (wires/in): 100 x 100
% open Area: 64%
ρ for titanium is 4.3x10^-8 ohm x m
I was thinking of using
R=(ρ)(Length)/(cross section area of wire)
im not an electrical engineer, so any guidance what's so ever would be a great help. Thank you everyone.