- #1
laxboi33
- 9
- 0
A .20- kg mass attached to a spring is pulled back horizontally across a table so that the potential energy of the system is increased from zero to 120 J. Ignoring friction, what is the kinetic energy of the system after the mass is released and has moved to a point where the potential energy has decreased to 80 J.
PE= 1/2 k*x^2
KE= 1/2 m*v^2
F= -kx
How would I find the spring constant or PE without the distance of the spring?
PE= 1/2 k*x^2
KE= 1/2 m*v^2
F= -kx
How would I find the spring constant or PE without the distance of the spring?