Calculating Spring Constant of Bungee Cord

In summary, the conversation is about calculating the spring constant of a bungee cord for a bungee jumper with a mass of 77.0kg. The jumper touches the water below and then oscillates 8 more times in 48.0 seconds. The equations F = -kx and T = 2π√(m/k) are used to solve for the spring constant, with the period being 6 seconds (48/8). The calculated spring constant is 8.94, but there is uncertainty about the accuracy.
  • #1
HHippo
1
0

Homework Statement


A bungee jumper with a mass of 77.0kg, jumps from a high bridge. He just touches the water in the river below and after reaching this lowest point, he oscillates up and down, hitting the lowest point another 8 times in 48.0 seconds. Calculate the spring constant of the bungee cord.

Homework Equations


F = -kx
T = 2π√(m/k)


The Attempt at a Solution


I thought the period was 6 (48/8) and then used those two equations to solve for k. Got 8.94 but I am not sure if I did it right...
 
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  • #2
Hi HHippo, welcome to PH.
Will you please show your calculations?
 
  • #3
You know the period and mass you can solve for the spring constant directly from the period equation. Check your math.
 
  • #4
method seems correct show your calculations
 
  • #5


I would approach this problem by first clarifying some information. Is the bungee cord assumed to be ideal, meaning it has no mass and does not stretch? Also, what is the initial length of the bungee cord and how much does it stretch when the jumper reaches the lowest point? These details are important in accurately calculating the spring constant.

Assuming that the bungee cord is ideal and has an initial length of 0, we can use the formula T = 2π√(m/k) to calculate the spring constant. In this equation, T represents the period, which is the time it takes for the jumper to complete one full oscillation up and down. In this case, the period is 6 seconds (48 seconds/8 times), so we can plug in the values and solve for k.

6 = 2π√(77/k)
6/2π = √(77/k)
(6/2π)^2 = 77/k
k = 77/(6/2π)^2 = 2.62 N/m

Therefore, the spring constant of the bungee cord is 2.62 N/m. It is important to note that this is an ideal calculation and in reality, the spring constant may vary depending on the actual length and properties of the bungee cord. Additionally, the mass of the jumper may also affect the spring constant. Further experimentation and analysis would be needed to determine the exact value of the spring constant in a real-world scenario.
 

Related to Calculating Spring Constant of Bungee Cord

1. What is a spring constant?

A spring constant, also known as a force constant, is a measurement of the stiffness of a spring. It represents the amount of force required to stretch or compress a spring by a certain distance.

2. How do you calculate the spring constant of a bungee cord?

The spring constant of a bungee cord can be calculated by dividing the force applied to the cord by the change in length of the cord. This can be expressed as k = F/x, where k is the spring constant, F is the force applied, and x is the change in length.

3. What units are used to measure spring constant?

Spring constant is typically measured in units of Newtons per meter (N/m) or pounds per inch (lb/in).

4. How does the length of a bungee cord affect its spring constant?

The longer the bungee cord, the lower the spring constant will be. This is because a longer cord will stretch more easily than a shorter cord, requiring less force to achieve the same change in length. The opposite is true for a shorter cord.

5. Can the spring constant of a bungee cord change over time?

Yes, the spring constant of a bungee cord can change over time due to factors such as wear and tear, temperature changes, and stretching. It is important to regularly check and adjust the spring constant of a bungee cord to ensure safety and optimal performance.

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