- #1
toothpaste666
- 516
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Homework Statement
How close to the edge of the 26.0-kg table shown in the figure (Figure 1) can a 64.0-kg person sit without tipping it over?
Homework Equations
∑F = 0 ∑T = 0
The Attempt at a Solution
forces A (left leg) and B (right leg) are the forces from the two legs of the table and x is the distance of the person from the right edge of the table (what i am trying to find)
∑F = A +B - 26g - 64g = 0
= A + B = 90g
= A + B = 882
for the torques I chose leg A as the pivot point
∑T = -(.6)26g + (1.2)B -[(1.7-x)64g] = 0
= -15.6g + 1.2B - (108.8g-x64g) = 0
= -15.6g + 1.2B -108.8g + x64g = 0
= -152.88 +1.2B -1066.24 +627.2x = 0
= 1.2B + 627.2x = 1219.12
I have 2 equations but 3 unknowns. What am I missing here? please help :(