Calculating Surface of Revolution for a Torus | Math Problem Solution

In summary, the conversation is about finding the surface area of a torus using the equation for a surface of revolution. The distance to the center of the torus and the radius are given in the problem. The equation for the surface of revolution is \[x^2 + (y - 12)^2 = 2^2\], and solving for y gives two possible functions. The next step is to use these functions to find the volume of the torus. A helpful resource for this problem is given as well.
  • #1
opticaltempest
135
0
Hello,

I am trying to find the surface area of a torus. I know there are equations
for finding this but in this problem I must use a surface of revolution.

Given in the problem is the distance to the center of the torus is 12 and
the radius of the torus is 2.

By using the equation for a circle I come up with the following
equation for my surface of revolution,

[tex] \[(x - h)^2 + (y - k)^2 = r^2\] [/tex]

I replace x with 0 since I suppose it doesn't matter where on the
x axis I revolve this surface. The equation becomes,

[tex] \[x^2 + (y - 12)^2 = 2^2\] [/tex]

Expanding,

[tex] \[x^2 + y^2 - 24y + 140\] [/tex]

Solving for y,

[tex] \[y = \pm \left( {\sqrt {4 - x^2 } - 12} \right)\] [/tex]

A quick plot in Maple to show my surface of revolution,

http://img256.imageshack.us/img256/5137/surfacecopy0df.jpg

I am confused on where I go next because y is not a function of x,
nor is x a function of y. Do I need have two different surfaces of
revolution? The top half of the circle and the bottom half of the
circle?
 
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  • #2
Yes, use just what you have.
But it is not
[tex] \[y = \pm \left( {\sqrt {4 - x^2 } - 12} \right)\] [/tex]
it is
[tex] y = 12 \pm\sqrt {4 - x^2 } [/tex]
One function is
[tex] y = 12+ \sqrt {4 - x^2 } [/tex]
and the other is
[tex] y = 12-\sqrt {4 - x^2 }[/tex]
 
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  • #3
Fifty Ways To Find The Volume Of A Torus

opticaltempest said:
...[tex] \[x^2 + (y - 12)^2 = 2^2\] [/tex]...
Solving for y,
[tex] \[y = \pm \left( {\sqrt {4 - x^2 } - 12} \right)\] [/tex]

A quick plot in Maple to show my surface of revolution,

http://img256.imageshack.us/img256/5137/surfacecopy0df.jpg

I am confused on where I go next because y is not a function of x,
nor is x a function of y. Do I need have two different surfaces of
revolution? The top half of the circle and the bottom half of the
circle?

There is a perfect answer to your exact question: check this out,http://www.math.umn.edu/~drake/pdfs/fifty-ways.pdf , it starts on the bottom of pg 2, under the heading (3) Slip out the back, Jack.

Basically:

Vol(torus) = Vol(upper semi-circle rotated about the x-axis) - Vol(lower semi-circle rotated about the x-axis).

Have fun :smile: .
 
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FAQ: Calculating Surface of Revolution for a Torus | Math Problem Solution

What is a surface of revolution?

A surface of revolution is a three-dimensional geometric shape that is created by rotating a two-dimensional curve around an axis. The resulting surface has rotational symmetry around the axis of rotation.

What are some examples of surfaces of revolution?

Some common examples of surfaces of revolution include spheres, cones, cylinders, and tori (donuts). These shapes can be created by rotating a circle, line, or other curve around a central axis.

What are the mathematical principles behind surfaces of revolution?

The mathematical principles behind surfaces of revolution involve concepts such as integration, derivatives, and parametric equations. These principles are used to calculate the surface area, volume, and other properties of a surface of revolution.

How are surfaces of revolution used in real life?

Surfaces of revolution have many practical applications in engineering, architecture, and design. For example, they are often used to create smoothly curved surfaces in car bodies, ship hulls, and other objects. They are also used in the production of pottery and in the design of furniture.

What are some limitations of surfaces of revolution?

One limitation of surfaces of revolution is that they are only suitable for creating symmetrical objects. Additionally, not all three-dimensional shapes can be created through rotation, so surfaces of revolution may not be able to accurately represent certain complex objects. Furthermore, the calculations involved in working with surfaces of revolution can be quite complex and time-consuming.

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