Calculating Temp Loss for Mixing Water Streams

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In summary, the problem at hand is determining the temperature loss when mixing two streams of water, one flowing at 2,400 gph at 85 degrees (F) and the other at 37,000 gph. The final temperature can be calculated using a weighted average of the two stream temperatures and a mass and energy balance equation. The enthalpy at the exit can be found using a steam table or database, and can be interpolated if necessary.
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cweed
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I am working to determine what the temperature loss (minimal at best) would be by mixing a stream of water flowing at 2,400 gph at 85 degree (f) into another stream of water flowing at 37,000 gph. Any help would be great
 
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Do you mean you just need the final temperature of the mixture? That would be a weighted average of the two stream temperatures.
 
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Yes the final temperature of the two stream the one at flowing 2,400 gph is 85 (f) and the one flowing at 37,000 gph is 105 (F).
 
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cweed said:
Yes the final temperature of the two stream the one at flowing 2,400 gph is 85 (f) and the one flowing at 37,000 gph is 105 (F).

This would be a typical mixing chamber type problem, but you'll need to know the pressure. The mass and energy balance yields:

[tex] h_3 = \frac{\dot{m_1}h_1 + \dot{m_2}h_2}{\dot{m_1} + \dot{m_2}} [/tex]

The m_dots with subs 1 and 2 are the respective mass flow rates coming into the mixing chamber. The h's are the respective enthalpies. They can be looked up in a steam table based on the inlet temperatures. This assumes of course that the inlet temperatures are below the saturation temperature of water at the specified pressure (i.e. it is in the compressed liquid state). Assuming that criterion is satisfied, the enthalpy of a compressed liquid can be approximated as a saturated liquid at the given temperature.

Once you have the enthalpy at the exit (h_3) you can look up the corresponding temperature in a steam table (or REFPROP if you have that database). If the exact enthalpy doesn't appear in your table you can interpolate and get a reasonable answer (depending on what accuracy you want).

Hope that helps.

CS
 

FAQ: Calculating Temp Loss for Mixing Water Streams

How do you calculate temperature loss for mixing water streams?

The formula for calculating temperature loss for mixing water streams is: (T1 x V1 + T2 x V2) / (V1 + V2) = Tm, where T1 and T2 are the temperatures of the two water streams, V1 and V2 are the volumes of the two water streams, and Tm is the resulting mixed temperature.

What units should be used for the temperatures and volumes in the calculation?

The temperatures should be in degrees Fahrenheit or Celsius, and the volumes should be in gallons or liters.

Are there any factors that can affect the accuracy of the temperature loss calculation?

Yes, there are several factors that can affect the accuracy of the calculation, such as the flow rates of the water streams, the efficiency of the mixing process, and any heat loss from the mixing vessel.

Is there a specific method for measuring the temperatures and volumes to use in the calculation?

There is no specific method, but it is important to use consistent units and measure the temperatures and volumes accurately to ensure an accurate calculation. It is also recommended to take multiple measurements and average them for a more precise result.

Can this calculation be used for other types of fluids besides water?

Yes, this calculation can be used for any type of fluid as long as the units for temperature and volume are consistent. However, different fluids may have different properties that can affect the accuracy of the calculation, so it is important to consider these factors when using this formula for non-water fluids.

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