Calculating Tension and Reaction Forces in an Overhead Garage Door System

In summary, the conversation discusses the components and setup of a 70 kg overhead garage door. The door consists of a rectangular panel supported by a cable and two sets of frictionless rollers. The rollers have different types of channels for movement. The conversation then asks for the tension in the cable and the reaction at each of the four channels. A possible solution involves calculating the moment around point B and using Fx=0 and Fy=0 to find the answers. However, the person is still seeking clarification and further assistance.
  • #1
Jaspworld
4
0
A 70 kg overhead garage door consists of a uniform rectangular panel AC, 2100 mm high, supported by the cable AE attached at the middle of the upper edge of the door and by two sets of frictionless rollers A and B. Each set consists of 2 rollers located on either side of door. The rollers A are free to move in horizontal channels, while the rollers B are guided by vertical channels. If the door is held in the position for which BD =1050 mm, determine
a.) Tension in cable AE
b.) Reaction at each of the four channels

(For an image go to http://www.freewebsite.0nyx.com/images/garage.bmp Sorry for the crappy image. I made it in paint and by the way, that G is supposed to be W.)
 
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  • #2
Any thoughts...?
 
  • #3
I'm not too sure but..

I think I can calculate the moment around point B and then get the value for A. Then I can let Fx=0 and Fy=0 and get the rest of the answers.

Does this make sense?
 
  • #4
Help

How come my thread ended up on the third page! I still need help..
 

Related to Calculating Tension and Reaction Forces in an Overhead Garage Door System

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