Calculating Tension in a Suspended Rope with a 50kg Weight

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The tension in the rope is calculated based on the weights it supports. At the top of the rope, the tension is the sum of the weight of the rope (100N) and the weight of the suspended object (500N), totaling 600N. At the bottom of the rope, the tension only accounts for the weight of the suspended object, which is 500N. The calculations confirm that the tension at the top is 600N and at the bottom is 500N. This understanding of tension in a suspended rope is crucial for physics applications.
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[moderator: text edited to change the phrasing.]

There is a question that that says: a 50 kg weight is suspended from the bottom part from a rope.

If the rope has a weight of 100N. Then what is the tension at each end of the rope( the top part connected to the ceiling and the bottom part to the weight)?

my answer is like that
At the top: the tension is equal to the weight of the rope and the weight so it would be :
100N +500N= 600 N ( g=10)
And at the bottom it’s:
Just the weight, so 500 N. Am i right?
 
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Yes.
 
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PeroK said:
Yes.
Appreciate your quick response
Thanks^^
 

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