- #1
mashedpotato
- 2
- 0
Hi, this is my first forum post - sorry if I'm in the wrong place, or I've done something wrong!
Here goes: There is a beam of 0.5m length hinged to a wall at a right angle with 200N mass at the end of the beam. This is supported by a wire T at angle 30°. The question asks to find tension in T.
It seems I can answer the question correctly, however, looking at the solutions, I do not understand why an answer was obtained in such a way...
Turning Moment = force x distance.
Ok, so I made the triangle into a trigonometry problem. Opposite = wall, Adjacent = beam and Hypotenuse = Wire / Tension.
Opp = 200N, I want to find Hyp ∴ Hyp = 200 / sin(30) = 400N. This answer is actually correct, but the answers use this as a solution:
T sin(30) x 0.5 = 200 x 0.5
If someone could please help, I would be extremely grateful, as this question has been frustrating me for some time.
mashedpotato.
Homework Statement
Here goes: There is a beam of 0.5m length hinged to a wall at a right angle with 200N mass at the end of the beam. This is supported by a wire T at angle 30°. The question asks to find tension in T.
It seems I can answer the question correctly, however, looking at the solutions, I do not understand why an answer was obtained in such a way...
Homework Equations
Turning Moment = force x distance.
The Attempt at a Solution
Ok, so I made the triangle into a trigonometry problem. Opposite = wall, Adjacent = beam and Hypotenuse = Wire / Tension.
Opp = 200N, I want to find Hyp ∴ Hyp = 200 / sin(30) = 400N. This answer is actually correct, but the answers use this as a solution:
T sin(30) x 0.5 = 200 x 0.5
If someone could please help, I would be extremely grateful, as this question has been frustrating me for some time.
mashedpotato.