Calculating the current of a circuit- resistance and volatge known, see picture

In summary: But actually, you can just substitute the value of I(1) from equation #3 into equations #1 and #2, and get I(2) in terms of I(3). Then set those two equations equal to each other and solve for I(3), which will give you the current through all three resistors. You get 1.37 A for that, and that's the correct answer. But your derivation looks long and involved.- I then calculated the current through each individual resistor using Ohm's Law.I(1)= V(1)/ R(1)= 1AI(2)= (I(3)R(3) - V(2))/ R(2)=
  • #1
mmoadi
157
0

Homework Statement



What current flows through the resistors R(1) = 1Ω, R(2) = 2 Ω and R(3) = 3 Ω, if the driving voltages are V(1) = 1V and V(2) = 2V?

Picture:
http://item.slide.com/r/1/151/i/lvtwIwH-0j8A8o-XAKDtPRQO1eHAb4Ik/

Homework Equations



V= RI → I= V/ R

The Attempt at a Solution



V(1)= I(2)R(2) + I(1)R(1)
V(2)= I(3)R(3) – I(2)R(2)
I(1)= I(2) + I(3)

- From what I stated above, I conclude three equations:

1) V(1) = I(2)R(2) + [(I(2) + I(3))*R(1)]
2) V(2)= I(3)R(3) - I(2)R(2)
3) V(1)= [I(2)*( R(1) + R(2))] + I(3)R(1)

- I combined the three equations and simplify for the current that goes through ALL resistors, which in our case is I(3):

I(2)= (I(3)R(3) - V(2))/ R(2)
V(1)R(2)= [(I(3)R(3) – V(2))/ R(2))*(R(2) + R(1))] + I(3)R(1)R(2)
(V(1)R(2))/ (R(2) + R(1))= (I(3)R(3)) + [I(3)R(1)R(2))/ (R(2) + R(1))]
I(3)*[R(3) + (R(1)R(2)/ (R(2) + R(1))]= [V(1)R(2)/ (R(2) + R(1))] + V(2)

I(3)= [(V(1)R(2)/ (R(2) + R(1)) + V(2)] / [R(3)* (R(1)R(2)/ (R(2) + R(1))]
I(3)= 1.37 A

Are my calculations correct?
Thank you for helping!:smile:
 
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  • #2
mmoadi said:

Homework Statement



What current flows through the resistors R(1) = 1Ω, R(2) = 2 Ω and R(3) = 3 Ω, if the driving voltages are V(1) = 1V and V(2) = 2V?

Picture:
http://item.slide.com/r/1/151/i/lvtwIwH-0j8A8o-XAKDtPRQO1eHAb4Ik/

Homework Equations



V= RI → I= V/ R

The Attempt at a Solution



V(1)= I(2)R(2) + I(1)R(1)
V(2)= I(3)R(3) – I(2)R(2)
I(1)= I(2) + I(3)

- From what I stated above, I conclude three equations:

1) V(1) = I(2)R(2) + [(I(2) + I(3))*R(1)]
2) V(2)= I(3)R(3) - I(2)R(2)
3) V(1)= [I(2)*( R(1) + R(2))] + I(3)R(1)

Equation #3 here is the same as equation #1, just written slightly differently... so you really have only two independent equations. I'd just start from the original three you had above.

mmoadi said:
- I combined the three equations and simplify for the current that goes through ALL resistors, which in our case is I(3):

I(2)= (I(3)R(3) - V(2))/ R(2)
V(1)R(2)= [(I(3)R(3) – V(2))/ R(2))*(R(2) + R(1))] + I(3)R(1)R(2)
I don't see where that last line comes from. The units are off, so something must be wrong in there.
 
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  • #3


I would like to commend you for your thorough and detailed approach in solving this problem. Your calculations appear to be correct and your method is sound. However, I would suggest double-checking your equations and calculations to ensure accuracy. Also, it would be helpful to label your final answer with the appropriate units (in this case, amperes). Overall, great job!
 

FAQ: Calculating the current of a circuit- resistance and volatge known, see picture

How do I calculate the current in a circuit when the resistance and voltage are known?

To calculate the current in a circuit, you can use Ohm's Law which states that current (I) is equal to voltage (V) divided by resistance (R). In other words, I = V/R. So if you know the values of voltage and resistance, you can simply divide the voltage by the resistance to find the current.

What units should be used for resistance and voltage in the calculation?

Resistance is measured in Ohms (Ω) and voltage is measured in Volts (V). It is important to use the correct units in the calculation to ensure accuracy.

Can the current in a circuit be negative?

Yes, the current in a circuit can be negative. This occurs when the direction of the current is opposite to the direction of the flow of electrons. However, in most cases, the current is considered positive as it flows in the direction of the circuit.

What is the relationship between resistance and current in a circuit?

The relationship between resistance and current is inverse. This means that as resistance increases, the current decreases and vice versa. This is because a higher resistance makes it more difficult for current to flow through the circuit.

How do I calculate the total current in a series circuit?

In a series circuit, the current is the same at all points. To calculate the total current, you can simply add up the values of individual currents in the circuit. For example, if there are two resistors in series with values of 2Ω and 4Ω, the total resistance would be 6Ω. If the voltage is 12V, the current would be 12V/6Ω = 2A.

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