- #1
satycorn
- 7
- 0
Hi everyone! I've got to problems I need your help with, I would really appreciate it if you could help me.
1. Homework Statement
A conductor made out of copper (Cu) has a resistance of 4Ω in 20° Celcius. When current flows in the conductor, it's temperature rises to 220°C. In parallel with the resistance, we connect a Rx resistance. How should the value of the Rx resistance be, compared to the original resistance, so that a greater heat can be released in the Rx? For Copper: α=0.0039, ρo=1.7x10-8
Q=I2Rt; Q=(U2/R)t
So since the resistances are connected in parallel, I tried using the first one but I don't have the time, do I have to build the solution in form of a ratio?? And also, why do we need the ρo of Copper if the R=Ro(1+αΔt) formula is used, in my opinion? Can anyone please help me with this?
Thank you :)!
1. Homework Statement
A conductor made out of copper (Cu) has a resistance of 4Ω in 20° Celcius. When current flows in the conductor, it's temperature rises to 220°C. In parallel with the resistance, we connect a Rx resistance. How should the value of the Rx resistance be, compared to the original resistance, so that a greater heat can be released in the Rx? For Copper: α=0.0039, ρo=1.7x10-8
Homework Equations
Q=I2Rt; Q=(U2/R)t
The Attempt at a Solution
So since the resistances are connected in parallel, I tried using the first one but I don't have the time, do I have to build the solution in form of a ratio?? And also, why do we need the ρo of Copper if the R=Ro(1+αΔt) formula is used, in my opinion? Can anyone please help me with this?
Thank you :)!