Calculating the Height Needed to Break the Sound Barrier When Dropped

[crybaby]

Sooo i was wondering...
Can something that has been dropped from a higj enough hight eventually break the sound barrier. Well, since we know that the gravitational acceleration is approximately 10 m/s^2 and that the speed of sound is approximately 330 m/s i pluged it into the acceleration formula:

a=dv/t
10=330/t
10t=330
t=33 s

So that told me that something has to fall 33 s to reach the speed of sound. Now that i know that it needs 33 s I am going to plug it into this formula:

s=(at^2)/2
s=(10*33^2)/2
s=5*33^2
s=5445m

So i think i calculated the hight from which something has to be dropped to reach the speed of sound but i need you guys to tell me iff this is actually correct. Sooo if you have time please answer ;)
ps. english is not my native language so please excuse my ridiculously bad grammar.

 

[fresh_42]

https://en.wikipedia.org/wiki/Felix_Baumgartner

The difficulty in your calculations is that the sound barrier depends on the density of the air, resp. the altitude, see
https://en.wikipedia.org/wiki/Speed_of_sound

 

[crybaby]

Ohh, thanks i didnt know that, but could my calculations be close or at least partially correct.