- #1
crybaby
Sooo i was wondering...
Can something that has been dropped from a higj enough hight eventually break the sound barrier. Well, since we know that the gravitational acceleration is approximately 10 m/s^2 and that the speed of sound is approximately 330 m/s i pluged it into the acceleration formula:
a=dv/t
10=330/t
10t=330
t=33 s
So that told me that something has to fall 33 s to reach the speed of sound. Now that i know that it needs 33 s I am going to plug it into this formula:
s=(at^2)/2
s=(10*33^2)/2
s=5*33^2
s=5445m
So i think i calculated the hight from which something has to be dropped to reach the speed of sound but i need you guys to tell me iff this is actually correct. Sooo if you have time please answer ;)
ps. english is not my native language so please excuse my ridiculously bad grammar.
Can something that has been dropped from a higj enough hight eventually break the sound barrier. Well, since we know that the gravitational acceleration is approximately 10 m/s^2 and that the speed of sound is approximately 330 m/s i pluged it into the acceleration formula:
a=dv/t
10=330/t
10t=330
t=33 s
So that told me that something has to fall 33 s to reach the speed of sound. Now that i know that it needs 33 s I am going to plug it into this formula:
s=(at^2)/2
s=(10*33^2)/2
s=5*33^2
s=5445m
So i think i calculated the hight from which something has to be dropped to reach the speed of sound but i need you guys to tell me iff this is actually correct. Sooo if you have time please answer ;)
ps. english is not my native language so please excuse my ridiculously bad grammar.
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