- #1
mathmari
Gold Member
MHB
- 5,049
- 7
Hey!
How could we calculate the following limits without the L'Hospital rule?
$$\lim_{x\rightarrow 0}\frac{\sin (x)-x+x^3}{x^3} \\ \lim_{x\rightarrow 0}\frac{e^x-\sin (x)-1}{x^2}$$
Is the only way using the Taylor expansion? (Wondering)
How could we calculate the following limits without the L'Hospital rule?
$$\lim_{x\rightarrow 0}\frac{\sin (x)-x+x^3}{x^3} \\ \lim_{x\rightarrow 0}\frac{e^x-\sin (x)-1}{x^2}$$
Is the only way using the Taylor expansion? (Wondering)
Last edited by a moderator: