- #36
raviyank
- 4
- 0
sulphuric has 2 protons.
so ph =-log(0.0004)
=-(log4-4)
=-(0.6021-4)
=3.3979
so ph =-log(0.0004)
=-(log4-4)
=-(0.6021-4)
=3.3979
raviyank said:sulphuric has 2 protons.
so ph =-log(0.0004)
=-(log4-4)
=-(0.6021-4)
=3.3979
Borek said:2.8g of NaOH it is.