- #1
hallwayantics
- 6
- 0
Hi was hoping someone out there could help me out with this problem.
http://en.wikipedia.org/wiki/Poker_probability
I have looked over the poker probability wiki page, but I cannot figure out this homework problem:
"What is the probability that the hand dealt contains exactly two suits?"
I can justify several different approaches ... but that just means I'm wrong.
1)
(4 C 2) * ( (26 C 5) - 2*(13 C 5) )
ie choose two suits, then from those 26 cards choose 5. Now subtract the two flush hands.
2)
(4 C 2)(26 C 5) - (4 C 1)(13 C 5)
ie get the number of hands with at most two suits then subtract the number of flush hands. (4 C 1)(13 C 5) is the number of flush hands in poker.
3)
(4 C 2)(26 C 5)
JMM
http://en.wikipedia.org/wiki/Poker_probability
I have looked over the poker probability wiki page, but I cannot figure out this homework problem:
"What is the probability that the hand dealt contains exactly two suits?"
I can justify several different approaches ... but that just means I'm wrong.
1)
(4 C 2) * ( (26 C 5) - 2*(13 C 5) )
ie choose two suits, then from those 26 cards choose 5. Now subtract the two flush hands.
2)
(4 C 2)(26 C 5) - (4 C 1)(13 C 5)
ie get the number of hands with at most two suits then subtract the number of flush hands. (4 C 1)(13 C 5) is the number of flush hands in poker.
3)
(4 C 2)(26 C 5)
JMM