Calculating the Probability of Faulty Plumbing in Hotel Rooms: A Case Study

In summary, the probability of a client being assigned a room with faulty plumbing is 5.4% and the probability that a person with a room having faulty plumbing was assigned accommodation at the Lakeview Motor Lodge is 44.4%.
  • #1
Roohul Amin
5
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Dear all Please help in solving the following problem.
A large industrial firm uses 3 local motels to provide overnight accommodations for its clients. from past experience, it is known that 20% of the clients are assigned rooms at the Ramada Inn, 50% at the sheeraton and 30% at the Lakeview Motor Lodge. if the plumbing is faulty in 5% of the rooms at the Ramada Inn, in 4% of the rooms at the Sheraton and in 8% of the rooms at the Lakeview Motor Lodge, what the probability that
a) A client will be assigned a room with faulty plumbing?
b) A person with a room having faulty plumbing was assigned accommodation at the Lakeview Motor Lodge?
I have come with the following solution.
Let L: a client is assigned accommodation at Lakeview Motor Lodge
R: a client is assigned accommodation at Ramada Inn
S: a client is assigned accommodation at Sheraton
P(Lf): Probability of faulty plumbing rooms in Lakeview=0.08
P(Rf): Probability of faulty plumbing rooms in Ramada=0.05
P(Sf): Probability of faulty plumbing rooms in Sheraton=0.04
Now
a) P(client assigned with faulty plumbing room)=P(Lf/L)+P(Rf/R)+P(Sf/S)
=0.3*0.08+0.2*0.05+0.5*0.04
b) P(faulty plumbing room in Lakeview)=P(L/Lf)
=0.08*0.3

Needs help
 
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  • #2
Roohul Amin said:
Dear all Please help in solving the following problem.
A large industrial firm uses 3 local motels to provide overnight accommodations for its clients. from past experience, it is known that 20% of the clients are assigned rooms at the Ramada Inn, 50% at the sheeraton and 30% at the Lakeview Motor Lodge. if the plumbing is faulty in 5% of the rooms at the Ramada Inn, in 4% of the rooms at the Sheraton and in 8% of the rooms at the Lakeview Motor Lodge, what the probability that
a) A client will be assigned a room with faulty plumbing?
b) A person with a room having faulty plumbing was assigned accommodation at the Lakeview Motor Lodge?
I have come with the following solution.
Let L: a client is assigned accommodation at Lakeview Motor Lodge
R: a client is assigned accommodation at Ramada Inn
S: a client is assigned accommodation at Sheraton
P(Lf): Probability of faulty plumbing rooms in Lakeview=0.08
P(Rf): Probability of faulty plumbing rooms in Ramada=0.05
P(Sf): Probability of faulty plumbing rooms in Sheraton=0.04
Now
a) P(client assigned with faulty plumbing room)=P(Lf/L)+P(Rf/R)+P(Sf/S)
=0.3*0.08+0.2*0.05+0.5*0.04
b) P(faulty plumbing room in Lakeview)=P(L/Lf)
=0.08*0.3

Needs help
Your answer for a) is 0.3*0.08+0.2*0.05+0.5*0.04 = 0.054, which is correct.

For b), you need to know what proportion of the clients with faulty plumbing were staying at Lakeview. In other words, you need to know $$\dfrac{\text{P(faulty plumbing room in Lakeview)}}{\text{P(client with faulty plumbing room)}} = \dfrac{0.024}{0.054}.$$
 
  • #3
Imagine 1000 clients. 20%, 200, are assigned the Ramada Inn, 50%, 500, the Sheraton, and 30%, 300, the Motor Lodge.

Of the 200 assigned to the Ramada Inn, 5%, 10, have faulty plumbing. Of the 500 assigned to the Sheraton, 4%, 20, have faulty plumbing, and of the 300 assigned to the Motor Lodge, 8%, 24, have faulty plumbing. That is a total of 10+ 20+ 24= 54, out of 1000 who have faulty plumbing- 54/1000= 0.054 or 5.4% are assigned a room with faulty plumbing. Of those 54, 24 were assigned to the Motor Inn. Given that a person had faulty plumbing, the probability they were assigned to the Motor Inn is 24/54= 0.444 or 44.4%.
 

FAQ: Calculating the Probability of Faulty Plumbing in Hotel Rooms: A Case Study

What is conditional probability?

Conditional probability is the probability of an event occurring given that another event has already occurred. It is denoted by P(A|B), where A is the event of interest and B is the condition.

How is conditional probability calculated?

Conditional probability is calculated by dividing the probability of the joint occurrence of events A and B by the probability of event B. This can be represented by the formula P(A|B) = P(A and B) / P(B).

What is an example of conditional probability?

An example of conditional probability is the probability of getting a head on a coin flip given that the coin is fair. This can be represented as P(heads|fair coin) = P(heads and fair coin) / P(fair coin), where P(heads and fair coin) is the probability of getting a heads on a fair coin and P(fair coin) is the probability of the coin being fair.

What is the difference between conditional probability and unconditional probability?

Unconditional probability is the probability of an event occurring without any conditions or prior knowledge. On the other hand, conditional probability takes into account a specific condition or prior event when calculating the likelihood of an event occurring.

How is conditional probability used in real life?

Conditional probability is used in various fields, such as statistics, finance, and science, to make predictions and decisions based on existing data. For example, in medicine, conditional probability is used to calculate the likelihood of a patient having a certain disease based on their symptoms and medical history.

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