- #1
CoolDude420
- 201
- 9
- Homework Statement
- In sampling system the sample rate is 500 Ms/s with an input signal of range of 1 V
peak−peak and a clock jitter of 1 ps rms . A performance of 60 dB is required for all
signals the Nyquist baseband. Calculate its size of the capacitor.
- Relevant Equations
- Analog-to-Digital Conversion by Marcel Pelgrom Book
First, I calculate the jitter power with an equation given in the book
Next, I calculate the signal power
Now, I know that SNR = Psignal/(Pjitter + PthermalNoise),
However, I seem to be getting a negative value for the thermal noise power?? My plan was to use this thermal noise power and equate it to kT/C to get my capacitor size. But the thermal power is negative??
What am I doing wrong?
Next, I calculate the signal power
Now, I know that SNR = Psignal/(Pjitter + PthermalNoise),
However, I seem to be getting a negative value for the thermal noise power?? My plan was to use this thermal noise power and equate it to kT/C to get my capacitor size. But the thermal power is negative??
What am I doing wrong?