- #1
superjen
- 26
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Sand is falling into a cone whose height is always 1/2 the diameter of the base. If the sand is falling at a rate of 1/2 cubic meters per min. How fast is the height increasin when the pile is 3 meters high?
so far I've drawn my diagram and got this far.
Given:
h = 1/2 the base
dv/dt = +1/2m3/min
Needs:
dh/dt
the equation i was going to use is
V = 1/12pih3
then i get
dv/dt = (1/2pi)(3h2)dh/dt
i don't know how to get the h?
any help?
so far I've drawn my diagram and got this far.
Given:
h = 1/2 the base
dv/dt = +1/2m3/min
Needs:
dh/dt
the equation i was going to use is
V = 1/12pih3
then i get
dv/dt = (1/2pi)(3h2)dh/dt
i don't know how to get the h?
any help?