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Homework Statement
A tall,cylindrical chimney falls over when its base is ruptured.Treat the chimney as a thin rod of length ##55.0m##.At the instant its makes an angle of ##35.0^°## with the vertical as it falls,what are the (a) ##a_r## of the top ? (b) ##a_t## of the top ? (Hint:Use energy considerations,not a torque )
Homework Equations
##mgh=\frac 1 2Iw^2##
The Attempt at a Solution
##L=55m##
For tangential veloctiy I found ##\frac 1 2Mg(L-Lsin(35))=\frac 1 2(\frac 1 3ML^2)(\frac {(V_{tan})^2} {L^2})##
from that I get ##V_{tan}=26.27 \frac m s##
I stucked here... I thought ##\frac {V_{tan}} {rt}=∝##
##t## is the time that end point comes that angle.
but it didnt worked out.
##a_r=\frac {(v_r)^2} {r}## I don't know how to find radial velocity...
Thanks