- #1
OldSnake
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Homework Statement
Here's a little drawing I made with all the info. In case my drawing is unclear. R1 is 100 kilo omhs
R2 is 100 kilo omhs as well. The current is 36,5 uA over the digital Ampere meter , And 0,4 Volt over the analog volt meter
Homework Equations
U= I x R
In a parallel currentflow U1=U2=U3
In a serieflow I1=I2=I3
The Attempt at a Solution
I'm completely baffled by this one. They're asking for the voltage of the resistance, but which one? Do they want me to add them together and are we even allowed to do that?
So R1+R2=R3 Which is 200k omh, but we still don't know the current over the resistance.
But we know the voltage over the voltage meter which is 0,4 Volt so the voltage over R3 is 0,4 V as well. Using I=U/R The current over R3 Is 0,000002 A. So the voltage of the resistance with voltmeter is 0,4 V, but how do you calculate it when you leave the voltmeter out of the picture?