- #1
DJJB
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So I am an engineering student working on co-op and I ran into a problem.
I have a resistor like the image above. I placed this resistor in free space, leads in vertical position (Ambient: 296K ) and I placed 10W of electrical power into it. What I need to find is the thermal coefficient (How much thermal energy is transmitted to the air from the aluminium outer casing)
I placed 6 thermocouples, one on each side and recorded the following temperatures:
Front: 442K
Back: 486K
Sides x 2: 462K
Bottom: 453K
Is anyone aware of a method to convert surface temperature of a given solid to power? So far I have only come across thermal conductivity which is dependent on thickness. Hopefully there is an easier solution which one of you may know. Thanks.
I have a resistor like the image above. I placed this resistor in free space, leads in vertical position (Ambient: 296K ) and I placed 10W of electrical power into it. What I need to find is the thermal coefficient (How much thermal energy is transmitted to the air from the aluminium outer casing)
I placed 6 thermocouples, one on each side and recorded the following temperatures:
Front: 442K
Back: 486K
Sides x 2: 462K
Bottom: 453K
Is anyone aware of a method to convert surface temperature of a given solid to power? So far I have only come across thermal conductivity which is dependent on thickness. Hopefully there is an easier solution which one of you may know. Thanks.